"Ultimate Jeopardy"

[joshg]

ABC 7 in L.A. 'breaks' the news that Ken and past champions will compete in a 15 week 'ultimate' tourney to find the absolute best Jeopardy! player ever. Top prize - $2 million. The games will start in February and conclude in May.

Wow, sweep to sweep. What a concept!

Josh

[cmjb13]

Well the staff would be complete idiots not to find a way to bring him back.

I like this idea better than having Ken face people who gave him the most competition.

[ClockGameJohn]

[quote name=\'cmjb13\' date=\'Dec 28 2004, 07:47 PM\']I like this idea better than having Ken face people who gave him the most competition.

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I'm sure at least one person here doesn't.  ;-)

[zachhoran]

[quote name=\'matchgame\' date=\'Dec 28 2004, 07:44 PM\']ABC 7 in L.A. 'breaks' the news that Ken and past champions will compete in a 15 week 'ultimate' tourney to find the absolute best Jeopardy! player ever. Top prize - $2 million. The games will start in February and conclude in May.

Wow, sweep to sweep. What a concept!

Josh

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Any word on how the format will work.

[OntarioQuizzer]

[quote name=\'matchgame\' date=\'Dec 28 2004, 08:44 PM\']ABC 7 in L.A. 'breaks' the news that Ken and past champions will compete in a 15 week 'ultimate' tourney to find the absolute best Jeopardy! player ever. Top prize - $2 million. The games will start in February and conclude in May.

Wow, sweep to sweep. What a concept!

Josh

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Linkage?

[GS Warehouse]

[quote name=\'OntarioQuizzer\' date=\'Dec 28 2004, 08:07 PM\']Linkage?

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The addy for KABC Channel 7 in L.A. is abc7.com.  However, I did a search for "ultimate jeopardy" on that site and the first headline to come out is "Saddam Hussein deserves 'Ultimate Penalty'".

(BTW, Andy, I thought One-Word-Post day wasn't until January 8--the anniversary of P+'s debut. :-D)

[joshg]

No link yet... it was broadcast on their 4PM news. I checked the website to post a link and I didn't see any. Alex mentioned that 150 past players will be funneled down to Ken and 2 other players. Last place $$$ is $250,000, 2nd place gets $500,000.

I'm sure the story will show up somewhere on their website...

Josh

[SplitSecond]

[quote name=\'matchgame\' date=\'Dec 28 2004, 06:24 PM\']No link yet... it was broadcast on their 4PM news. I checked the website to post a link and I didn't see any. Alex mentioned that 150 past players will be funneled down to Ken and 2 other players. Last place $$$ is $250,000, 2nd place gets $500,000.
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I wish I was given a guaranteed berth in a tournament final where I could walk away with no less than a quarter mil.

I'm glad I'm not one of the other 150.

[zachhoran]

[quote name=\'SplitSecond\' date=\'Dec 28 2004, 08:54 PM\'][quote name=\'matchgame\' date=\'Dec 28 2004, 06:24 PM\']No link yet... it was broadcast on their 4PM news. I checked the website to post a link and I didn't see any. Alex mentioned that 150 past players will be funneled down to Ken and 2 other players. Last place $$$ is $250,000, 2nd place gets $500,000.
[/quote]
I wish I was given a guaranteed berth in a tournament final where I could walk away with no less than a quarter mil.

I'm glad I'm not one of the other 150.

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WHo would one pick for the two players most likely to challenge Ken in that final game?

[OntarioQuizzer]

[quote name=\'zachhoran\' date=\'Dec 28 2004, 09:58 PM\'][quote name=\'SplitSecond\' date=\'Dec 28 2004, 08:54 PM\'][quote name=\'matchgame\' date=\'Dec 28 2004, 06:24 PM\']No link yet... it was broadcast on their 4PM news. I checked the website to post a link and I didn't see any. Alex mentioned that 150 past players will be funneled down to Ken and 2 other players. Last place $$$ is $250,000, 2nd place gets $500,000.
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I wish I was given a guaranteed berth in a tournament final where I could walk away with no less than a quarter mil.

I'm glad I'm not one of the other 150.

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WHo would one pick for the two players most likely to challenge Ken in that final game?

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I'd wait to see the full field myself before picking, personally...

[mmb5]

Since I was sworn to secrecy, I'll give it in a math problem.   Ken needs two opponents.  Those two opponents won their games against four other opponents.  Those other four opponents also won a game at some point.  Using this information, how many players will be needed to fill 75 shows?


--Mike

[Don Howard]

Hmmm. Three full months where the contestants are playing for points--not for dollars. This would then be going longer than 1986's All-American Scrabble Tournament.
I thought the Jeopardy! web site might have something on this. Stosh's Place has nothing, either, but maybe he's waiting for confirmation from cbs.com

[TunaHead]

Why do I get this gut feeling I smell a major dud story here? I've searched high and low on the net to no avail. And 15 weeks? That sounds vaguely familiar to an idea posted on here...

But soon, I bet someone high up in the realm will pick up on this as true news... I'm just waiting for it...

[Matt Ottinger]

[quote name=\'Don Howard\' date=\'Dec 28 2004, 11:00 PM\']I thought the Jeopardy! web site might have something on this. Stosh's Place has nothing, either, but maybe he's waiting for confirmation from cbs.com[/quote]
This is yet another one of those times when our own members are ahead of the curve on a breaking story.    I too have been sworn to secrecy (strangely, by two different sources...), but I'm sure all the details will come out soon enough.  I see huge plusses and huge potential minuses for the stunt, and there will be plenty of opportunity for us to discuss them all between now and...whenever.

[Robert Hutchinson]

[quote name=\'mmb5\' date=\'Dec 28 2004, 09:30 PM\']Since I was sworn to secrecy, I'll give it in a math problem.   Ken needs two opponents.  Those two opponents won their games against four other opponents.  Those other four opponents also won a game at some point.  Using this information, how many players will be needed to fill 75 shows?[/quote]

Not enough information. With an extremely high number of wild card slots in the early rounds, I get a possible field as low as 57. There may be a lower possible number--I just added brackets in reverse, each bracket letting all but three players advance until the quarter-finals, and then tacked on players to get to a round 75 shows at the end/beginning.

Changing the number of wild cards gives lots and lots of different possible answers.

No wild cards means either that some games will have a number of players other than 3, or that some game winners will not advance to the next round(s), AFAICT.